(x^2-x-2)(x+2)=0

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Solution for (x^2-x-2)(x+2)=0 equation: 


Simplifying
(x2 + -1x + -2)(x + 2) = 0

Reorder the terms:
(-2 + -1x + x2)(x + 2) = 0

Reorder the terms:
(-2 + -1x + x2)(2 + x) = 0

Multiply (-2 + -1x + x2) * (2 + x)
(-2(2 + x) + -1x * (2 + x) + x2(2 + x)) = 0
((2 * -2 + x * -2) + -1x * (2 + x) + x2(2 + x)) = 0
((-4 + -2x) + -1x * (2 + x) + x2(2 + x)) = 0
(-4 + -2x + (2 * -1x + x * -1x) + x2(2 + x)) = 0
(-4 + -2x + (-2x + -1x2) + x2(2 + x)) = 0
(-4 + -2x + -2x + -1x2 + (2 * x2 + x * x2)) = 0
(-4 + -2x + -2x + -1x2 + (2x2 + x3)) = 0

Combine like terms: -2x + -2x = -4x
(-4 + -4x + -1x2 + 2x2 + x3) = 0

Combine like terms: -1x2 + 2x2 = 1x2
(-4 + -4x + 1x2 + x3) = 0

Solving
-4 + -4x + 1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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